Question on: JAMB Mathematics - 2007
If the lines 2y - kx + 2 = 0 and y + x - (\frac{k}{2}) = 0 intersect at (1, 2), find the value of k
A
-2
B
-4
C
-1
D
-3
Ask EduPadi AI for a detailed answer
Correct Option: A
2y - kx + 2 = 0, @ x = 1, y = -2
2(-2) - k(1) + 2 = 0
-4 - k + 2 = 0
k = -2
Or y + x - (\frac{k}{2}) = 0, @ x= 1, y = -2
-2 + 1 - (\frac{k}{2}) = 0
-1 = (\frac{k}{2})
k = -1 x 2
= -2
Add your answer
Please share this, thanks!
No responses